A farmer has enough food to feed 20 animals in his cattle for 6 days. How long 3 would the food last if there were 10 more animals in his cattle?
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Answer:
Let the food will now last for x days. Then,
Number of animals 20/6 30/x
Number of days
Clearly, more is the number of animals, less will be the number of days for food to last.
So, it is a case inverse proportion.
∴ 20 × 6 = 30x ⇒ x =
30
20×6
= 4
Hence, the food will now last for 4 days.
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