A Farmer has enough Food to feed 20 animals in his cattle for 5 days. How long the Food
fast if would there were 25 animals in his cattle.
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It's a case of inverse proportion
Therefore, No. of cattle: 20 l 25
No. of days:. 5 l x
Therefore, 20×5= 25x
= x= 20×5÷6= 3.33 days
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