Question

Find the area of the quadrilateral ABCD if a diagonal AC= 22cm and the corresponding altitudes from opposite vertices B and D are BM=3cm and DN= 3cm.​

Answer 1

Answer:

Step-by-step explanation:

diagonal=22 cm

offsets=3cm ,3cm

area of quadrilateral= 1/2 *diagonal*(sum of offsets)

=1/2*22*(3+3)

11*6=66 cm sq

Answer 2

Answer:

66cm^2

Step-by-step explanation:

here, AD=BC (both 3 cm)eq. 1

BM perpendicular to BC

DN perpendicular to AC

in area of triangle ABC =half into base into height

b=AC=22cm

h=BM=3cm

(1/2×22×3)cm

=33cm^2

similarly, triangle of ADC=33cm^2 (by eq. 1)

area of quadrilateral ABCD = area of triangle ABC +area of triangle ADC

=33cm^2 + 33cm^2

=total area of ABCD = 66cm^2

hence, this your answer,

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