Question

A farmer has enough food to feed 30 animals in his cattle for 4 days. How long would the food last if there were 10 less animals in his cattle?​

Answer 1

Answer:

PLZ MARK AS BRAINLIEST !

Step-by-step explanation:

For 30 animals 4 days For 1 animal 4*30= 120 days. For (30-10)=20 animals 120/20= 6 days. Lesser the number of animals, leser the daily food conumption and more number of days do the rations last. So, if there were 20 animals, the number of days the food would last be 6 days.

Answer 2

$\huge\bf\underline{\underline{Question}}$

A farmer has enough food to feed 30 animals in his cattle for 4 days. How long would the food last if there were 10 less animals in his cattle?

$\huge\bf\underline{\underline{Solution}}$

Let the number of days be x

If 10 animals are removed, we'll be left with 20 animals

We will use Unitary Method for this sum.

$30 \times 4 = 20 \times x \\ = 3 0 = 5 \times x \\ = x = 6$

Therefore, number of days = 6 ☑