Question

a farmer has to go 500 m due north 100 m due east and 200 m due south to reach his field,
If he takes 20 min po reach the field, what is the average velocity of farmer during the walk?​

Answer 1

Answer:

Explanation:

Average velocity is defined as total displacement divided by total time.

$\longmapsto \bf{ Velocity_{(avg)} = \dfrac{Total \; displacement}{Total \; time} }$

Finding total displacement :

⇒ Total displacement = √{ED)² + (AE)²} m

⇒ Total displacement = √{(100)² + (300)²} m

⇒ Total displacement = √{10000 + 90000} m

⇒ Total displacement = √{100000} m

⇒ Total displacement = 100√10 m

∴ Total displacement is 100√10 m.

Finding total time :

• He takes 20 min to reach the field.

⇒ Total time = 20 minutes

⇒ Total time = (20 × 60) seconds

⇒ Total time = 1200 seconds

∴ Total time taken is 1200 seconds.

Finding average velocity :

$\longmapsto \rm{ Velocity_{(avg)} = \dfrac{Total \; displacement}{Total \; time} }$

Substituting the values.

$\longmapsto \rm{ Velocity_{(avg)} = \dfrac{100\sqrt{10}\; m}{1200 \; s} }$

$\longmapsto \rm{ Velocity_{(avg)} = \dfrac{1\sqrt{10} \; m}{12 \; s} }$

$\longmapsto \rm{ Velocity_{(avg)} = \dfrac{\sqrt{10} }{12} \; ms^{-1}}$

∴ Average velocity is √10/12 m/s.