A farmer have 18kg of urea and 10kg potassium.he mixes both of them and uses p kg of mixture for his farm.if farmer added (p-4.6)kg of potassium to remaining mixture,the new ratio of urea and potassium becomes 7:6.find what amount at potassium was added by farmer
Answers
Answer:
Amount of potassium added by farmer = 3.8 kg
Step-by-step explanation:
A farmer have 18kg of urea and 10kg potassium.he mixes both of them and uses p kg of mixture for his farm.if farmer added (p-4.6)kg of potassium to remaining mixture,the new ratio of urea and potassium becomes 7:6.find what amount at potassium was added by farmer
Urea = 18 kg
Potassium = 10 kg
Total Mixture = 18 + 10 = 28 kg
p kg mixture used
means urea used = (18/28)p = 9p/14 kg
potassium used = (10/28)p = 5p/14 kg
Remaining urea = 18 - 9p/14 kg
Remaining potassium = 10 - 5p/14 kg
Potassium added = p - 4.6 kg kg
Final potassium in mixture = 10 - 5p/14 + p - 4.6 kg
= 5.4 + 9p/14 kg
the new ratio of urea and potassium becomes 7:6
(18 - 9p/14) : (5.4 + 9p/14) :: 7: 6
=>(18 - 9p/14) /(5.4 + 9p/14) = 7/6
=> 108 - 54p/14 = 37.8 + 63p/14
=> 70.2 = 117p/14
=> p = 8.4
Amount of potassium added by farmer = p - 4.6 kg
= 8.4 - 4.6
= 3.8 kg
Amount of potassium added by farmer = 3.8 kg