A farmer keeps rabbits in three large hutches that stand in a row in his backyard. Each of the hutches is painted different colours – red, yellow and green. Until recently, the number of rabbits in the green hutch was twice as large as the number of rabbits in the yellow hutch. Then, one day, the farmer took five rabbits out of the left-side hutch and gave them away to the local school’s pet corner. He also took half of the rabbits that remained in the left-side hutch and moved them to the red hutch.
What was the colour of the left-side hutch?
Answers
Answer:
The left-side hutch was green.
Explanation:
Given that the number of rabbits in the green hutch was twice as large as the number of rabbits in the yellow hutch, and the farmer took half of the rabbits from the left-side hutch and moved them to the red hutch, we can conclude that the number of rabbits in the left-side hutch before the transfer was larger than the number in the red hutch after the transfer.
Since we know the farmer took five rabbits out of the left-side hutch, the number of rabbits in the left-side hutch before the transfer was greater than 5. Thus, the left-side hutch was not red or yellow.
Therefore, the left-side hutch must have been green.
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Answer:
The answer is yellow.
Explanation:
As we already know at the outset the number of rabbits in the green hutch was twice as large as the number of rabbits in the yellow hutch. This means that the number of rabbits in the green hutch was an even number. After the farmer removed five rabbits from the left side hutch, then the number of rabbits that remained there also became an even number. This is proven by the fact that it was divisible by 2. Therefore, before those five were removed, the left side hutch contained an uneven number of rabbits hence the left side hutch cannot be the green one, but based on the given information, it cannot be the red one. Hence it is yellow.