Question

a farmer lift a sac of weight of 100kg to a height of 2 m. find work done​

Answer 1

Step-by-step explanation:

work done = force × displacement

in this case there is no displacement so

work done is zero

force ×0

= 0

so work done =0

Answer 2

Potential energy is energy due to position.

Potential energy is scalar quantity having magnitude.

Sl unit of P.E is Joules.

CGS unit of P.E is erg.

Potential energy of an object is given by

P.E = mgh

where,

P.E denotes potential energy.

m denotes mass.

g denotes gravitational field.

h denotes height.

Substituting all the given values in the formula,

➠ P.E = mgh

➠ 98000 = (100)(9.8)(h)

➠ 98000 = 980h

➠ h = 98000/980

➠ h = 100 m{.}.

thus, the height through which it is lifted is 100m.