Question

a farmer moves along boundary of a square field with side of 10cm in 40s. Find the magnitude of distance covered by farmer in 2 minutes. ​

Answer 1

Answer:

Heya friend

Here's your answer

Side of the square = 10 m

Perimeter of the square = 4×10 = 40 m

He completes 1 round in 40 s.

So, speed = 40/40 = 1 m/s

So, distance covered in 2 min 20 s or 140 s is = 140 × 1 = 140 m

Number of rounds of the square completed in moving through 140 m is = 140/40 = 3.5

In 3 rounds the displacement is zero. In 0.5 round the farmer reaches the diagonally opposite end of the square from his starting point.

Displacement = AC = (AB2 + BC2)1/2 = (100+100)1/2 = 10?2 m

Hope it helps

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Step-by-step explanation:

Answer 2

Answer:600cm

Step-by-step explanation

40 sec = 10cm

60 sec = 5 cm

60x2 =120 sec

=5x120=600 cm