Question

a farmer moves along boundary of field of side 10m in 40sec . What will be his displacement and distance covered at the end of 2min and 20sec from initial position ​

Answer 1

Answer:

Hi friend,

Total distance covered 10m in 40sec

Total time taken= 2min 20sec= 140sec

Total round completed = 140/40=3.5 rounds

So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.

AC2= AB2 +BC2 

AC2= (10)2 +(10)2

AC2= 100+100

AC2=200

AC = (200)1/2

 

AC= 10× (2) ½ 

Hope it helps......

Answer 2

Answer:

Hi friend,

Total distance covered 10m in 40sec

Total time taken= 2min 20sec= 140sec

Total round completed = 140/40=3.5 rounds

So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.

AC2= AB2 +BC2 

AC2= (10)2 +(10)2

AC2= 100+100

AC2=200

AC = (200)1/2

 

AC= 10× (2) ½ 

Hope it helps......

Explanation:

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