A farmer moves along the bondary of a square field of side 10 m in 40 sec. What will be the magnitude of displacement at the end of 2 min 40 sec?
Answers
Answer:
Side of the given square field = 10m
Perimeter of a square = 4 x side = 10 m x 4 = 40 m
Farmer takes 40 s to move along the boundary.
Displacement after 2 minutes 40 s = 2 x 60 s + 40 s = 160 seconds
since in 40 s farmer moves 40 m
Therefore, in 1s the distance covered by farmer = 40 / 40 m = 1m
Therefore, in 160s distance covered by farmer = 1 ? 160 m = 160 m.
Now, number of rotation to cover 140 along the boundary=
Total Distance / Perimeter
= 160 m / 40 m = 4 round
Thus, after 4 round farmer will at point C of the field.
Thus, Displacement AC = √10 m² + 10 m²
=√100 m² + 100 m²
=√200 m²
=10 √2 m
10 x 1.414 = 14.14 ,
Thus, after 2 min 40 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.
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Step-by-step explanation:
side= 10m
magnitude of displacement = 2 min
=120 sec +
40
=160 sec
therefore =160÷4
40 m
so, magnitude of displacement is 40 meter