Find the AH for the reaction given below. PC15(e) → PC13(%) + Cl2(g)
(A) AU - RT
(B) AU + 2RT
(C) AU + RT
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Answer:
(c)
Explanation:
We have
∆ H = ∆U+∆nRT
for ∆n = 1
∆H = ∆U + RT
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