Question

a farmer moves along the boundary of a sqare field 10m in 40sec . what will be magnitude of displacement of the farmer at the end of 2minutes 40sec​

Answer 1

Total distance 40m in 40 sec. Total time taken by the farmer = 2 min 20 sec. =140 seconds. Total rounds completed= 140/40=3.5 rounds That means if the farmer starts from point A of the square field, he reaches point C. Therefore, displacement is AC. Assume ABC is a right angled triangle. Therefore, AC2= AB2 +BC2 AC2= (10)2 +(10)2 AC2= 100+100 AC2=200 AC = (200)1/2 AC= 10× (2) ½

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Answer 2

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