A farmer moves along the boundary of a square field of side 10 m in 40 sec .What will be the magnitude of displacement of the farmer at the end of 2 min 20 sec from his initial position
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time taken for 1 journey= 40s
s(displacement)=?
2 mins 20s= 2 x 60+20
=140s
hyp^2 = base^2 + altitude^2
hyp^2 = 10^2 + 10^2
hyp^2 = 100 + 100
hyp^2 = 200
hyp = root 200m
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