Math, asked by dolmagupta123, 1 year ago

the product of archana age 5 years later with her age 8 years ago is 30 find her present age​

Answers

Answered by master55538
28

Answer:

present age be x

age of Archana 5 years later be x+5

age of Archana 8 years ago be x-8

now the product is 30

so

(x+5)(x-8)=30

x^2-8x+5x-40=30

x^2-3x-70=0

x^2-10x+7x-70=0

x(x-10)+7(x-10)=0

(x+7)(x-10)=0

x=10

let check....

15*2=30

30=30

here the answer here present age is 10

Answered by palkin
9

{\huge{\color{pink}\star{\mathfrak{\color{pink}{\underline{\underline{Answer :}}}}}}}

Let her present age be x.

So,

Her age after 5 years = x+5

Before 8 years = x -8

According to the question ..

(x+5)×(x-8)=30

=> x² - 3x - 40 = 30

x² - 3x - 70 = 0

{using middle term split method}

x² - 10 x + 7x -70 = 0

x(x-10) +7(x-10) = 0

(x+7) (x-10) = 0

Putting..

x+7 = 0

x = -7

and

x-10 = 0

x = 10

Rejecting x = -7 as age can't be negative.

syo, her present age (x) = 10

Her age after 5 years (x+5) = 15

Her age before 8 years (x-8) = 2

Verifying answer

15 × 2 = 30

\boxed{Hence \: Solved..!! }

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