A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
NCERT Class IX
Sciences - Main Course Book
Chapter 8. Motion
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Displacement is final position - initial position.
2 min 20 sec=140 sec
It makes 3 and a half rounds.
40/40 *140=140m
2 min 20 sec=140 sec
It makes 3 and a half rounds.
40/40 *140=140m
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