Question

A farmer moves along the boundary of a square field of side 10m in 40s.what will be the magnitude of displacement of the farmer at the end of 2minutes 20seconds from his initial position

Answer 1

Answer:

The answer is 5m

Explanation:

By the formula of speed=distance/time the speed of farmer is,s=10m/40s = 0.25m/s

Now,time=2min 20s

So (2×60)+20= 140s, applying again the formula Speed=distance/time

We have speed=0.25,time=140s

•'• distance=35m but displacement=5m by drawing the figure as square is concerned