a farmer moves along the boundary of a square field of side 10 m in 40 seconds. what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds and what is the total distance covered by him
Answers
Answered by
0
Answer:
The answer is (10√2) m.
Answered by
2
Answer:
displacement = 5m
total distance = 35m
Explanation:
perimeter of square = 4 x side = 4 x 10 = 40 m
Speed of farmer = distance/time
= 10/40 = 0.25 m/s
2 minutes 20 seconds = 2 x 60 + 20 seconds
= 140 seconds
distance = speed x time
= 0.25 x 140 = 35 m
Since the perimeter of field is 40 m ,
the farmer is (40 - 35 ) m from the starting point
= 5 m from starting point
:. total distance coverede= 35m
displacement = 5m
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