Question

A farmer moves along the
boundary of a square field of side
10 m in 40 s. What will be the
magnitude of displacement of the
farmer at the end of 2 minutes 20
seconds from his initial position?
​

Answer 1

Answer:

V=40m/40s=1m/s

t=2min 20 sec =2×60+20

=140sec

=4×30+20

displacement of DB=10 ×root 2

final answer is 10 root 2

EXPLANATION:

the farmer having 10m for each side so now add each side then it is equal to 40m now 40m and 40sec then it is equal to 1m/s

and in 2min 20sec we have 120 sec and add +20 sec

now distance let 40 m be distance

time taken for 10m of all sides is equal to 40s then for 40m it takes so the final distance is 1 distance and displacement are different from each other distance is long and displacement is short mean distance is measured or taken in long way but displacement is measured with short and the way also is short path

Answer 2

Answer:

please mark as brainliest