Question

a farmer moves along the boundary of a square field of side 10 metre in 40 second what will be the magnitude....
it's physics question not of maths...​

Answer 1

Explanation:

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Answer 2

Answer:

AC of the square field.

Applying Pythagoras theorem in right angle triangle ADC, we get

Hypotenuse? = Base? + Height?

→ AC2 = ADP + DC2

AC? = 102 + 102 = 200

AC = V200 - = 102m

Hence the net displacement if the farmer after 3.5 rounds is equal to 10 v2m.

Therefore, the magnitude of

displacement of the farmer at the end of 2 minutes 20 seconds from his initial

position is 102m.

Explanation:

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