A farmer moves along the boundary of a square field of side 10 m 40 sec. what will be magnitude of displacement of the farmer at the end of 2 minutes 20 seconds ???
Answers
Answered by
10
Perimeter of SQ field = 40m;
t1 = 40s;
Speed of 1 round = 1m/s
t2 = 2m20s = 140s;
Distance = speed * time
→ 1 * 140
= 140m;
Distance = 140m;
Displacement = 14.14m;
t1 = 40s;
Speed of 1 round = 1m/s
t2 = 2m20s = 140s;
Distance = speed * time
→ 1 * 140
= 140m;
Distance = 140m;
Displacement = 14.14m;
Answered by
9
hope. it will help u. .. ..
Attachments:
Similar questions