Physics, asked by ankitshekhar78pa921x, 1 year ago

A farmer moves along the boundary of a square field of side 10 m 40 sec. what will be magnitude of displacement of the farmer at the end of 2 minutes 20 seconds ???

Answers

Answered by nitishm7777
10
Perimeter of SQ field = 40m;
t1 = 40s;

Speed of 1 round = 1m/s

t2 = 2m20s = 140s;
Distance = speed * time 
→ 1 * 140
= 140m;

Distance = 140m;
Displacement  = 14.14m;


Answered by Akshaypanigrahi
9
hope. it will help u. .. ..
Attachments:
Similar questions