Question

A farmer moves along the boundary of a square field of side 10 m. in 40 s. What will be the

magnitude of displacement of the farmer at the end of 2 minutes 20 seconds​

Answer 1

Farmer takes 40 s to move along the boundary. Thus, after 3.5 round farmer will at point C of the field. Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.

Answer 2

Answer:

14.14m

Explanation:

Given side of square =10m, thus perimeter P=40m

Time taken to cover the boundary of 40 m =40 s

Thus in 1 second, the farmer covers a distance of 1 m

Now distance covered by the farmer in 2 min 20 seconds = 1×140=140m

Now the total number of rotation the farmer makes to cover a distance of 140 meters =

$\frac{total \: distance}{perimeter} = \frac{140}{40} = 3.5$

At this point, the farmer is at a point say B from the origin O

Thus the displacement

$s = \sqrt{10 {}^{2} + 10 ^{2} }$

Pythagoras theorem.

$s = 10 \sqrt{2} = 14.14m \:$

Please mark me as brainlist...