Question

A farmer moves along the boundary of a square field of side 10 m in 40 seconds what will be the magnitude of displacement of the farmers at the end of 2 minutes 20 seconds

Answer 1

Total distance = perimeter of square= 4×10m=40m.
Time taken=40s
Therefore, total time taken by farmer =2min 20seconds=140 seconds
Therefore,140/40=3.5
Therefore the farmer completes 3 and half round of the square,i.e.,if he starts from A he reaches point c after 2 min 20 seconds.
Therefore,displacement is AC.
To find AC ,assume a triangle ADC inside a square .
In triangle ADC
AC square is equal to AD square +DC square
AC square = (10)*2+ (10)*2
AC square= 100+100
AC square= 200
=10√2m.