a farmer moves along the boundary of a square field of side 10 m in 40 second what will be the magnitude of displacement of the farmer at the end of 2 minute 20 seconds from its initial position
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Total distance covered 10m in 40sec
Total time taken= 2min 20sec= 140sec
Total round completed = 140/40=3.5 rounds
So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by Pythagoras theorem.
AC^2= AB^2 +BC^2
AC^2= (10)^2 +(10)^2
AC^2= 100+100
AC^2=200
AC = (200)1/2
AC= 10× (2) ½
Total time taken= 2min 20sec= 140sec
Total round completed = 140/40=3.5 rounds
So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by Pythagoras theorem.
AC^2= AB^2 +BC^2
AC^2= (10)^2 +(10)^2
AC^2= 100+100
AC^2=200
AC = (200)1/2
AC= 10× (2) ½
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