Question

a farmer moves along the boundary of a square field of side 10 metre in 40 second what will be the magnitude of displacement in 2 minutes 40 seconds​

Answer 1

hey mate

here is your answer

Answer:

after 160s (2min 40s),the farmer would have completed 4 complete rounds of the field.

So,his final position would be same as initial position

thus,

the displacement will be 0.

Answer 2

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here is your answer mate.

⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️

perimeter of square = 10+10+10+10

perimeter = 40 meters

farmer take 40 second to take one round of the field.

it mean his speed = 40/40 m/s.

the farmer cover 1 metre in 1 second.

now 2 minutes 40 second = 160 second.

total round = 4

so the farmer cover 4 round in 2 minutes 40 second.

thanks for giving me the opportunity to help you.