A farmer moves along the boundary of a square field of side 10 m in 40 seconds
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Correct Question :
A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds?
Solution :
Distance covered by farmer in 40 seconds
(40 × 1)m = 40 m
Speed of the farmer = distance/ time = 40m/40s
= 1m/s
Total time given the question = 2 min
20 s = 60 + 60 + 20 = 140s
Since, he completes 1 second of the field in 40 seconds so he will complete 3 rounds in 120s (2min) or 120m distance is covered in 2 min. In another 20 seconds will cover another 20m so total distance covered in 2 min 20s = 120 + 20 = 140m
DISPLACEMENT =>
= √10² + 10² = 200
= 10√2
= 10 × 1.414
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