Question

a farmer moves along the boundary of a square field of side 10 metre in 40 seconds what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position​

Answer 1

Answer:

Explanation:

After 120 sec distance =120 m

Displacement= 0m

2 min 20 sec=140 sec

For 20 sec the distance will be half

20 meter

The displacement will be √200

Answer 2

10√2

Given,side of the square field=10m Therefore,perimeter=10*4=40m Farmer moves along the boundary in 40 second Time= 2 min 20 sec = 2*60+20=140s since,in 40 sec farmer moves 40 m Therefore,in 1 sec distance covered by farmer =40/40=1m Therefore,in 140 sec distance covered by farmer=1*140=140m

Now, number of rotation cover 140 along the boundary = Total distance/perimeter

=140/40=3.5 round

Thus after 3.5 round farmer will at point B

Therefore, Displacement = √10*10+10*10

=√200=10√2 ans

This, after 2 min 20 sec the displacement of farmer will be equal to

10√2 north east from initial position