Question

A farmer moves along the boundary of a square ground of side 50 m in 200 sec.The magnitude of displacement of the farmer at the end of 11 minutes 40 seconds from his initial position is
50 m
150 m
200 m
50√2 m

Answer 1

Answer:

Displacement= 50√2 m

Step-by-step explanation:

Perimeter of Square boundary = 4×a = 4×50

= 200 m

Speed of farmer= distance/ time

= 200m/ 200 sec

= 1 m/sec

Time for which farmer travelled = 11 min 40

= 11×60+ 40 sec= 700 sec

Distance travelled in 700 sec = 700 m

So farmer moved three turn and half turn of the field.

In three turn he reach the initial point and in half turn he will be at a diagonal distance from initial point

Displacement = 50√2 m

Answer 2

Answer:

perimeter= 4×50 m = 200 m

farmer completes 1 round around the square in 200 sec i.e. 1 meter in 1 sec.

11 minutes 40 sec = 700 sec

in 700 sec , farmer will complete 3 rounds & then 2 sides

do, displacement= length of the diagonal of the square= 50√2 m