Physics, asked by reshmachavan872, 3 months ago

a farmer moves along the boundary of field of sides 3 cm into 5 cm in 20 seconds what will be the magnitude of distance and displacement of farmers at the end of 2 minutes 20 seconds​

Answers

Answered by vagdevigaar
1

Explanation:

Farmer takes 40 s to move along the boundary. ... Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position. 3.

Answered by Tubamir
0

Total distance covered 10m in 40sec

Total time taken =2min 20sec=140sec

Total round completed 140/40=3.5 rounds

so if an object move from A to D, the shortest path will be from A to C. so displacement is AC, that We will find by phythogoras theorem.

AC2=AB2+BC2

AC2=(10)2+(10)2

AC2=100+100

AC2=200

AC=(200)1/2

AC=10×(2)½

Hope it's helpful

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