a farmer moves along the boundary of field of sides 3 cm into 5 cm in 20 seconds what will be the magnitude of distance and displacement of farmers at the end of 2 minutes 20 seconds
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Explanation:
Farmer takes 40 s to move along the boundary. ... Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position. 3.
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Total distance covered 10m in 40sec
Total time taken =2min 20sec=140sec
Total round completed 140/40=3.5 rounds
so if an object move from A to D, the shortest path will be from A to C. so displacement is AC, that We will find by phythogoras theorem.
AC2=AB2+BC2
AC2=(10)2+(10)2
AC2=100+100
AC2=200
AC=(200)1/2
AC=10×(2)½
Hope it's helpful
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