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A farmer moves along the boundry of a square Field of side lomin 40swhat will be the magnitude
of displacement of the farmer
at the end of 2 minutes 20.
seconds From his initial
position
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delete my answer my answer is wrong but the method is correct
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Answer:Speed=distance/time
=15.7s
Distance covered in 2m 20s=140s
=speed×time
=2198m
Displacement=no.of rounds=3.5
=200m
Explanation:
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