A farmer moves along the boundry of a square field of side 10 m in 40secs.What will be the magnitude of displacement of the farmer at the end of 2 min 20 secs from his initial position??
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Given
A square field of side 10 cm .Farmer move alongs it in 40 sec.
we have to find the magnitude of displacement in 2 min. 20 sec.
time=2×60 sec.+20sec.
=120 sec.+20 sec.
140 sec.
No.of revolution =total time /total time taken in one revolution
=140/40sec.
=3.5 sec
displacement =root under 10's square +10's square meter
=root under 100+100 meter
=root under 200 meter
=10root 2 meter
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