Math, asked by koushik31, 1 year ago

a farmer sold 2 bullocks for 24000.on first bullock he gain 25%.on second bullock he lost 20%. find gain or loss percent.

Answers

Answered by siddhartharao77
59
Total Selling Price for 2 bullocks = 24000 + 24000

                                                       = 48000.


Given that, on the 1st bullock, he gains 25%.

Cost Price of the 1st bullock = 24000 * 100/125

                                               = 19200.


Given that, on the 2nd bullock, he lost 20%.

Cost price of the 2nd bullock = 24000 * 100/80

                                                  = 30000.


Total cost price of 2 bullocks = 19200 + 30000

                                                 = 49200.


We know that Loss = CP - SP

                                  = 49200 - 48000

                                  = 1200.


We know that Loss% = (Loss/CP) * 100

                                    = (1200 * 100/49200)

                                    = 2.43%


Hope this helps!
Answered by lmeenareddy24
0

Answer:

Step-by-step explanation:

Given S.P of each Bullock = Rs 24000

(i)    Profit =S.P−C.P

⇒25% of C.P = S.P - C.P

⇒  

100

25

​  

C.P=24000 - C.P

⇒  

4

1

​  

C.P + C.P= 24000

⇒  

4

5

​  

C.P = 24000

⇒C.P = Rs 19200

(ii)Loss = C.P−S.P

⇒ 20% of C.P = C.P - S.P

⇒  

100

20

​  

 C.P = C.P - 24000

.⇒ C.P -  

5

1

​  

 C.P = 24000

⇒  

5

4

​  

 C.P = 24000

⇒C.P = 6000×5

⇒ C.P = Rs 30000

Now    Total S.P of 2 Bullocks = Rs 48000

            Total C.P of 2 Bullocks = Rs 19200 +Rs30000  

                                                    = Rs 49200

Profit = S.P−C.P

          = Rs 48200 - 48000

           = Rs 1200

Profit % =  

C.P

P

​  

×100

             =    

49200

1200

​  

×100

             =2.44

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