a farmer sold two bullocks of rupees 18000 grain 20% and on the other he lost 20% find his gain or loss percent on the whole transaction. by brainly
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Hi ,
1 ) cost of the Bullock = c.p.
Selling price ( s.p ) = Rs18000
Gain ( g ) = 20%
C.p.= ( 100 × s.p ) /( 100 + g )
= ( 100 × 18000 ) / ( 100 + 20 )
= 100 × 18000 / 120
= Rs 15000
2 ) loss ( l ) = 20%
S.p = Rs 18000
C.p of second Bullock
= ( 100 × s.p ) / ( 100 - l )
= ( 100 × 18000 ) / ( 100 - 20 )
= Rs 22500
3 ) Total c.p of two Bullock's = Rs 15000 + Rs 22500
= Rs 37500
Total s.p = Rs 18000 + Rs 18000
= Rs 36000
S.p < c.p
Therefore he gets loss
Loss = total c.p - total s.p
= 37500 - 36000
= Rs 1500
Loss % =( loss × 100) / c.p
= ( 1500 × 100 ) / 37500
= 4 %
I hope this helps you.
:)
1 ) cost of the Bullock = c.p.
Selling price ( s.p ) = Rs18000
Gain ( g ) = 20%
C.p.= ( 100 × s.p ) /( 100 + g )
= ( 100 × 18000 ) / ( 100 + 20 )
= 100 × 18000 / 120
= Rs 15000
2 ) loss ( l ) = 20%
S.p = Rs 18000
C.p of second Bullock
= ( 100 × s.p ) / ( 100 - l )
= ( 100 × 18000 ) / ( 100 - 20 )
= Rs 22500
3 ) Total c.p of two Bullock's = Rs 15000 + Rs 22500
= Rs 37500
Total s.p = Rs 18000 + Rs 18000
= Rs 36000
S.p < c.p
Therefore he gets loss
Loss = total c.p - total s.p
= 37500 - 36000
= Rs 1500
Loss % =( loss × 100) / c.p
= ( 1500 × 100 ) / 37500
= 4 %
I hope this helps you.
:)
Answered by
3
This is ur ans hope it will help you in case of any doubt comment below
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