Math, asked by jenilmaheshwari, 1 year ago

a farmer sold two bullocks of rupees 18000 grain 20% and on the other he lost 20% find his gain or loss percent on the whole transaction. by brainly

Answers

Answered by mysticd
8
Hi ,

1 ) cost of the Bullock = c.p.

Selling price ( s.p ) = Rs18000

Gain ( g ) = 20%

C.p.= ( 100 × s.p ) /( 100 + g )

= ( 100 × 18000 ) / ( 100 + 20 )

= 100 × 18000 / 120

= Rs 15000

2 ) loss ( l ) = 20%

S.p = Rs 18000

C.p of second Bullock

= ( 100 × s.p ) / ( 100 - l )

= ( 100 × 18000 ) / ( 100 - 20 )

= Rs 22500

3 ) Total c.p of two Bullock's = Rs 15000 + Rs 22500

= Rs 37500

Total s.p = Rs 18000 + Rs 18000

= Rs 36000

S.p < c.p

Therefore he gets loss

Loss = total c.p - total s.p

= 37500 - 36000

= Rs 1500

Loss % =( loss × 100) / c.p

= ( 1500 × 100 ) / 37500

= 4 %
I hope this helps you.

:)
Answered by tnwramit1
3
This is ur ans hope it will help you in case of any doubt comment below
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