A farsighted person cannot focus objects closer than 100 cm the lens that will permit him tobread from a dist of /40 cm hasva focal length of
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Answer:
Explanation:
Given A farsighted person cannot focus objects closer than 100 cm the lens that will permit him to read from a distance of 40 cm have a focal length of
So a farsighted person uses a convex lens
So u will be - 40 cm, v = 100 cm
We know that
1/f = 1/v - 1/u
1/f = 1/100 - (-1/40)
1/f = 1/100 + 1/40
1/f = 2 + 5 / 200
1/f = 7/200
or f = 200 / 7
f = 28.57 cm
So focal length will be 28.57 cm
Answered by
0
Answer:-
Given
V= 100 cm
u = 40 cm
focal length is given as
1/f = 1/v - 1/u
here
u = -40 cm
v = -100 cm
so,
1/f = (1/-100) - (1/-40)
1/f = (-2+5)/200
1/f = 3/200
or focal length
f = 200/3 cm = 66.67 cm
and power of lens
[here f = 66.67 cm = 0.66m]
P = 1/f
= > 1/0.66
=> 1.51 D
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@GauravSaxena01
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