Question

solve this question from trigonometric ​

Answer 1

Answer:

answer for the given problem is given

Answer 2

(1+tanx+secx) (1+cotx-cosecx)

[1+(sinx/cosx) +(1/cosx) ][1+(cosx/sinx) -(1/sinx) ]

[((cosx+sinx) +1)/cosx][((cosx+sinx) -1)/sinx]

using (a+b) (a-b) =a²-b²

={(cosx+sinx) ²-1}/cosx sinx

(cos²x+sin²x+2cosx sinx -1)/cosx sinx

now cos²x +sin²x=1

=(1-1+2cosxsinx)/cosx sinx

=2

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