Question

A farsighted person has a distant point of 200cm. He wanted to see objects that are very far clear how much the distance of focus and the power of the glass eye lens must be in use?

Answer 1

PR = 200 cm

P = __?
F = __?


The power of lens glasses
P = - 100 / PR
P = - 100/200
P = - ¹ / ₂ D 


Focal distance of lens glasses
F = - PR
F = - 200 cm = - 2 m 

Answer 2

-2m...................