Question

a faster train takes 1 hour less than a slow train for a journey of 200 km. if the speed of slowr train is 10 km per hour less than that of fastest train. find the speed of two trains

Answer 1

Answer:

40  & 50 km/Hr

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Step-by-step explanation:

Let say speed of slower train = S  km/hr

Speed of faster train = S+10 km /Hr

Time taken by slower train for 200 km =  200/S

Time taken by faster train for 200 km = 200/(S+10)

200/S  - 200/(S+10) = 1

200 (S+10) - 200S = S(S+10)

2000 = S^2 + 10S

S^2 + 10S - 2000 = 0

S^2 + 50S - 40S -2000 = 0

(S+50)(S-40) = 0

S = 40  as Speed can not be negative so -50 is not possible

Speed of slower train = 40 km/Hr

Speed of faster train = 40 + 10 = 50 km/Hr

Answer 2

Answer:

Step-by-step explanation:

40  & 50 km/Hr

Please mark the answer as "The Brainliest answer" if you like it

Step-by-step explanation:

Let say speed of slower train = S  km/hr

Speed of faster train = S+10 km /Hr

Time taken by slower train for 200 km =  200/S

Time taken by faster train for 200 km = 200/(S+10)

200/S  - 200/(S+10) = 1

200 (S+10) - 200S = S(S+10)

2000 = S^2 + 10S

S^2 + 10S - 2000 = 0

S^2 + 50S - 40S -2000 = 0

(S+50)(S-40) = 0

S = 40  as Speed can not be negative so -50 is not possible

Speed of slower train = 40 km/Hr

Speed of faster train = 40 + 10 = 50 km/Hr

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