Question

A faster train takes one hour less than a slower train for a journey of 200 km

Answer 1

Step-by-step explanation:

Let the speed of faster train be x km/hr.

∴ Speed of slower train = (x – 10) km/hr

200/(x - 10) - 200/x = 1

⇒ x2 – 10x – 2000 = 0

⇒ (x – 50) (x + 40) = 0

x = 50, –40 (rejected)

∴ Speed of faster train 50 km / hr

Speed of slower train 40 km / hr

Answer 2

Answer:

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Step-by-step explanation: