Math, asked by gassisingh68, 7 months ago

a father age is three time the sum of the ages of his two cgildren after five years his age will be two time if their ages find the presenr age of the father

Answers

Answered by khushant90
1

Answer:

A father’s age is three times the age of his two sons. After 5 years, his age will be twice the sum of the ages of his sons. What is the age of the father?

Answer : Let the age of the sons be x and y.

Given that Father’s age is three times the age of his two sons.

Therefore, present age of father is 3(x+y)

Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son.

Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5.

3(x+y)+5 = 2(x+5+y+5)

3x+3y+5 = 2x+10+2y+10

3x+3y+5 = 2x+2y+20

3x-2x+3y-2y = 20–5

x+y = 15

Now the age of father was 3(x+y)=3(15)=45 (Putting the value of x+y)

Thus the age of the father is 45.

Step-by-step explanation:

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Answered by haasiniarjun2064
0

Answer:

Let the age of the sons be x and y. Given that Father's age is three times the age of his two sons. Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son. Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5

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