Question

a father age is twice his sons age.ten years age he was thrice in age as his son.find their present ages.​

Answer 1

$\underline{\underline{\bold{Question\:Correction:}}}$

A father's age is twice his son's age. 10 years ago he was thrice in age as his son. Find their present ages.​

$\mathfrak{Answer:}$

Son's age = 20 years    &  Father's age = 40 years.

$\mathfrak{Step-by-Step\:Explanation:}$

Let the son's age be x years.

So the father's age = 2x years.

10 years ago,

• Son's age was = (x - 10) years.
• Father's age was = (2x - 10) years.

$\mathfrak{According\:to\:question:}\\\\\\\implies\tt{(x-10)3=2x-10}\\\\\\\implies\tt{3x-30=2x-10}\\\\\\\implies\tt{3x-2x=30-10}\\\\\\\implies\tt{x=20.}\\\\\\\boxed{\boxed{\bold{Son's\:age=20\:years\quad\&\quad Father's\:age=40\:years.}}}$

Answer 2

Let Present Age of Son=X years

Then,Age of Father=2x years
_______________
Ten Years Ago

Son Age=(x-10)

Father Age=(2x-10)
----------------------------
Father is Also Thrice the Age of Son
10 years Ago.
-----------------------------
Then

2x-10=3(x-10)

2x-10=3x-30

2x-3x=-30+10

-x=-20

X=20

Son=20 years

Father=2×20=40 years

$\boxed{\mathtt{\huge{Son=20\:Years}}}$

$\boxed{\mathtt{\huge{Father=40\:Years}}}$