Question

A father aged 42 years has a son aged 9.In how many years will the age of the son be one-fourth that of the father? ​

Answer 1

Step-by-step explanation:

Age of son = 9 years

Age of father = 42 years

Let the number of years be x.

Then,

9 + x = 1/4 × (42+x)

9 + x = 42/4 + 1/4x

x - 1/4x = 42/4 - 9

3/4x = 6/4

x = 2 years

Hope it helps!

Follow me!

Mark me brainliest!

Answer 2

Answer:

2 years

Step-by-step explanation:

Age of father= 42 years

Next time father will get an age which has a 1/4th = 44 years (after 2 years)

Age of son= 9 years (after 2 years = 11 years)

11 = 1/4th of 44

Hope it helps.

Please mark as brainliest.