a father ages 42years has a son aged 9. in how many years will be age of the son be one-fourth that of the father
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Answer:
2 years
Step-by-step explanation:
let the time be n years
then 42 + n = 4 ( 9 + n) [since age of son shoulf be one fourth of father]
removing parenthesis
42 + n = 36 + 4n
6 = 3n
2 = n
hence after 2 years age of son will be 1/4 of father
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