Question

a father is 20 year older than his son after 5 years the age of father will be twice that of his son find the present age of both

Answer 1

son present age=x
father present age=x+20
x+25= 2(x+5)
x=15
son age=15
father age= 35

Answer 2

✬Son Age = 15 Years ✬

✬ Father Age = 35 Years ✬

Step-by-step explanation:

Given:

• A father is 20 years older than son.
• After 5 years the age of father will be twice of his son.

To Find:

• What is the present ages of both ?

Solution: Let son's present age be x years. Therefore his father's age

➼ Father's age = 20 years more than x

➼ Father's age = (x + 20) Years

• Now after 5 years •

• Son age = (x + 5) Years
• Father age = (x + 20 + 5) = (x + 25) Years

A/q

$\implies{\rm }$ 2(x + 5) = (x + 25)

$\implies{\rm }$ 2x + 10 = x + 25

$\implies{\rm }$ 2x – x = 25 – 10

$\implies{\rm }$ x = 15

Hence , The present age of son is x = 15 years and

➟ Father's age = (x + 20) = 15+20 = 35 Years.