A father is 20 years older than his son. 12 years ago, the age of the father was six times that of his son. Find their present ages
Answers
Answered by
2
let the age of father be x and the son be y
there x=y+20
x-12=6(y-12)
y+20-12=6y-72
5y=80
y=16
x=16+20
x=36
father=36
son=16
Hope it helps
there x=y+20
x-12=6(y-12)
y+20-12=6y-72
5y=80
y=16
x=16+20
x=36
father=36
son=16
Hope it helps
divyanshtyagi20:
Correct man
plsss mark as the braniest answer
Similar questions