Question

A father is 24 years older than his son, After 8 years he will be three times as old as his son find their present ages​

Answer 1

Step-by-step explanation:

Let x = son’s age and x + 24 = the father’s age. Now add 10 years to each person

x + 10 (son) plus x + 24 + 10 (father) = 68

2x + 44 = 68

2x = 24

x = 12 (son)

12 + 24 = 36 (father)

So the son was 12 and the father was 36

12 + 10 (son) plus 36 + 10 (father) = 68 (in ten years)

Answer 2

Let son’s age be X
Father’s age = X+24
After 8 years
X+24 = 3X
3X - X = 24
2X = 24
X=24/2
X= 12
Father’s age = 3X
= 3*12
=36
Son’s age=X
=12