a father is 25 years older than his son . one year ago he was six times as old as his son. find their present age.
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Heya!!Here is your answer friend ⤵⤵
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⏪Let the age of son be X years
⏪The age of father becomes X + 25 years .
➡One year ago ages were
6 (X - 1). = ( X + 25 -1)
6X -6 = X +24
5X = 30
X=6
➡ Age of son = 6 years
➡Age of father = 31 years
Hope it helps you ✌✌
↔↔↔↔↔↔↔↔↔↔↔↔↔↔
⏪Let the age of son be X years
⏪The age of father becomes X + 25 years .
➡One year ago ages were
6 (X - 1). = ( X + 25 -1)
6X -6 = X +24
5X = 30
X=6
➡ Age of son = 6 years
➡Age of father = 31 years
Hope it helps you ✌✌
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