Question

a father is 25 years older than his son . one year ago he was six times as old as his son. find their present age.

Answer 1

Heya!!Here is your answer friend ⤵⤵
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⏪Let the age of son be X years

⏪The age of father becomes X + 25 years .

➡One year ago ages were

6 (X - 1). = ( X + 25 -1)

6X -6 = X +24

5X = 30

X=6

➡ Age of son = 6 years

➡Age of father = 31 years



Hope it helps you ✌✌