Question

A father is 3 times as old as his son. After 15 years, he will be twice old as his son, what are their present ages?

Answer 1

Answer:15;45

Step-by-step explanation:

Present age of son = x years

Present age of dad =3x

After 15 years

Son's age=x+15

Dad's age=3x+15

According to the question

2(x+15)=3x+15

2x+30=3x+15

X=15 years Son's age

3X=45 father's age

Answer 2

Answer:

Present age of son= x

Present age of father= 3x

Age of son (after 15 years)= x+15= y

Age of father (after 15 years)= 3x+15= 2y

=3x+15=2(x+15)

=3x+15= 2x+30

=3x-2x=30-15

=x=15

Therefore age of son=15

& age of father = 3×15

= 45