Math, asked by gokul9504, 1 year ago

A father is. 3 times old as son after 18 years the father will be on less than double the age of the son

Answers

Answered by Copella
0

Answer:

Present Age of son =17

Present Age of father =51

Step-by-step explanation:

Let age of father be x

Let age of son be y

x = 3y - (i)

Also,

x + 18 = 2 (y+18) - 1

x+18 = 2y + 36 - 1

x-2y=35-18

x = 17 + 2y - (ii)

Using (ii) in (i) ;

17 + 2y = 3y

17= y.

x = 3 (17)

x = 51

Thus, Present Age of son =17 & Present Age of father =51

Answered by Comella
0

Bonjour !! frnd.

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