A father is 30 year older than his son. In 12 year the man will be three time as old as his son find their pesent
bindhu78:
solution is 3
Answers
Answered by
67
[tex]\text{Let\:the\:present\:age\:of\:the\:son\:be\:x}[/tex]
[tex]\text{Thus,\:His\:Father's\:age\:will\:be\:(x+30)}[/tex]
[tex]\text{According\:to\:the\:question,}[/tex]
[tex]\implies \: 3(x + 12) = x + 30 + 12 \\ \\ \implies3x + 36 = x + 42 \\ \\ \implies3x - x = 42 - 36 \\ \\ \implies2x = 6 \\ \\ \implies \: x = \frac{6}{2} \\ \\ \implies \: x = 3[/tex]
[tex]\text{Thus,\:His\:Father's\:age\:will\:be\:3\:+\:30\:=\:33\:years}[/tex]
Answered by
44
Let the age age of the son be x.
Therefore, the age of the father=x+30.
After 12 years,
Son's age=x+12
Therefore father's age=3*(x+12)
=> x+12+3*(x+12)=x+12=x+30+12
=>x+12+3x+36=2x+54
=>4x+48=2x+54
=>4x-2x=54-48
=>2x=6
=>x=6/2=3
Ans) The son's age is 3 years and the father's age is 3+30=33 years.
Therefore, the age of the father=x+30.
After 12 years,
Son's age=x+12
Therefore father's age=3*(x+12)
=> x+12+3*(x+12)=x+12=x+30+12
=>x+12+3x+36=2x+54
=>4x+48=2x+54
=>4x-2x=54-48
=>2x=6
=>x=6/2=3
Ans) The son's age is 3 years and the father's age is 3+30=33 years.
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