A father is 30 years older than his son in 12 years the man will be 3 times as old as his son find their present ages
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Let the present age of father be x
And the present tags of son is y
According to the question
x=30+y
x-y=30. . . . 1
After 12 years
12+x=3(y+12)
12+x=3y+36
x-3y=36-12
x-3y=24. . . . 2
Subtract the equation no 1 from 2
y=3
Put the value of y. in equation no 1
x-y=30
x-3=30
x=33
Hope it helps you
And the present tags of son is y
According to the question
x=30+y
x-y=30. . . . 1
After 12 years
12+x=3(y+12)
12+x=3y+36
x-3y=36-12
x-3y=24. . . . 2
Subtract the equation no 1 from 2
y=3
Put the value of y. in equation no 1
x-y=30
x-3=30
x=33
Hope it helps you
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